20x^(2/3)-11x^(1/3)-42=0

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Solution for 20x^(2/3)-11x^(1/3)-42=0 equation: 


x in (-oo:+oo)

20*x^(2/3)-(11*x^(1/3))-42 = 0

20*x^(2/3)-11*x^(1/3)-42 = 0

t_1 = x^(1/3)

20*t_1^2-11*t_1^1-42 = 0

20*t_1^2-11*t_1-42 = 0

DELTA = (-11)^2-(-42*4*20)

DELTA = 3481

DELTA > 0

t_1 = (3481^(1/2)+11)/(2*20) or t_1 = (11-3481^(1/2))/(2*20)

t_1 = 7/4 or t_1 = -6/5

t_1 = -6/5

x^(1/3)+6/5 = 0

1*x^(1/3) = -6/5 // : 1

x^(1/3) = -6/5

( -6/5 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 7/4

x^(1/3)-7/4 = 0

1*x^(1/3) = 7/4 // : 1

x^(1/3) = 7/4

x^(1/3) = 7/4 // ^ 3

x = 343/64

x = 343/64

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